Q70 / 155 · WBJEE 2023 · Mathematics

Let \(A=\left(\begin{array}{ccc}2 & 0 & 3 \\ 4 & 7 & 11 \\ 5 & 4 & 8\end{array}\right)\). Then

  • Correct answer
    A
    \(\operatorname{det} A\) is divisible by 11
  • B
    \(\operatorname{det} A\) is not divisible by 11
  • C
    \(\operatorname{det} A=0\)
  • D
    A is orthogonal matrix

Solution

\(\begin{aligned} & \text {Hint: } \operatorname{det}(A)=2(56-44)+0+3(16-35) \\ & =24-57 \\ & =-33 \text { which is divisible by } 11 \end{aligned}\)

Hence, the correct answer is option: 'A'.

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