Let f:R→R be a function such that f2=4 and f^(')2=1. Then, the value of limx→2(x^2f2-4fx)/(x-2) is equal to

Question

Let f:R→R be a function such that f2=4 and f^(')2=1. Then, the value of limx→2(x^2f2-4fx)/(x-2) is equal to:

MARKS Content Team · Accepted Answer

Correct answer: (D) 12. Given, f2=4 So, the given limit is in 0/0 form. So, limx→2(x^2f2-4fx)/(x-2) Apply L'Hospital Rule limx→2(2xf2-4f^(')x)/1 =(44-4)/1=12

Let $f : R \to R$ be a function such that $f (2) = 4$ and $f^{'} (2) = 1 .$ Then, the value of $\lim_{x \to 2} \frac{x^{2} f (2) - 4 f (x)}{x - 2}$ is equal to:

Solution

Relevant Questions

Let f:R→R be a function such that f2=4 and f'2=1. Then, the value of limx→2x2f2-4fxx-2 is equal to:

Solution

Relevant Questions

Let $f : R \to R$ be a function such that $f (2) = 4$ and $f^{'} (2) = 1 .$ Then, the value of $\lim_{x \to 2} \frac{x^{2} f (2) - 4 f (x)}{x - 2}$ is equal to: