Let f:R→R be a function defined as fx=(x^2-6)/(x^2+2), then f is

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MARKS Content Team · Accepted Answer

Correct answer: (D) neither one-one nor onto. Since, fx=f-x ∴f is not one-one. Let, y∈R. Then, fx=y⇒y=(x^2-6)/(x^2+2) ⇒x^2=(6+2y)/(1-y) For x to be real, 6+2y1-y≥0 and 1-y≠0⇒y+3y-1≤0 and y≠1 ⇒-3≤y<1 ∴ Range of f=-3,1⊂R ∴ f is not onto

Let $f : R \to R$ be a function defined as $f (x) = \frac{x^{2} - 6}{x^{2} + 2},$ then $f$ is

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Let f:R→R be a function defined as fx=x2-6x2+2, then f is

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Let $f : R \to R$ be a function defined as $f (x) = \frac{x^{2} - 6}{x^{2} + 2},$ then $f$ is