$P$ is the circumcentre of $\triangle A B C$. If the position vectors of $A, B, C$ and $P$ are $\bar{a}, \bar{b}, \bar{c}, \frac{\bar{a}+\bar{b}+\bar{c}}{4}$ respectively, then the position vector of the orthocentre of this triangle is

• A

  $\bar{a}+\bar{b}+\bar{c}$
• Correct answer
  B

  $\frac{\bar{a}+\bar{b}+\bar{c}}{2}$
• C

  $-\left(\frac{\bar{a}+\bar{b}+\bar{c}}{2}\right)$
• D

  $\overline{0}$

Hence, the correct answer is option: 'B'.