Let $2 \overline{\mathrm{i}}-\overline{\mathrm{j}}-\overline{\mathrm{k}}, 5 \overline{\mathrm{i}}+\overline{\mathrm{j}}-2 \overline{\mathrm{k}},-13 \overline{\mathrm{i}}-11 \overline{\mathrm{j}}+4 \overline{\mathrm{k}}$ be the position vectors of three points A, $\mathrm{B}, \mathrm{C}$ respectively. If $\overline{\mathrm{AB}}=\lambda \overline{\mathrm{BC}}$ and $\overline{\mathrm{AC}}=\mu \overline{\mathrm{CB}}$, then $\lambda+\mu=$

• A

  $1$
• Correct answer
  B

  $-1$
• C

  $2$
• D

  $-2$

Hence, the correct answer is option: 'B'.