In a $\triangle \mathrm{ABC}$, if $\sin ^2 \mathrm{~B}=\sin \mathrm{A}$ and $2 \cos ^2 \mathrm{~A}=3 \cos ^2 \mathrm{~B}$, then the triangle is

• A

  acute angled
• Correct answer
  B

  obtuse angled
• C

  right angled
• D

  equilateral

Hence, the correct answer is option: 'B'.