$\mathrm{XeF}_2$ is isostructural with

• A

  $\mathrm{TeF}_2$
• Correct answer
  B

  $\mathrm{ICl}_2^{-}$
• C

  $\mathrm{SbCl}_3$
• D

  $\mathrm{BaCl}_2$

Solution

Species having the same number of bond pairs and lone pairs are isostructural (have same structure).
Thus, $\mathrm{XeF}_2$, is isostructural with $\mathrm{CCl}_2^{-}$and $\mathrm{BaCl}_2$.

Hence, the correct answer is option: 'B'.