Q4 / 222 · NTA Abhyas (NEET) 2020 · Physics · Wave Optics

In the ideal double-slit experiment, when a glass-plate (refractive index 1.5) of thickness t is introduced in the path of one of the interfering beams (wavelength λ), the intensity at the position where the central maximum occurred previously remains unchanged. The minimum thickness of the glass-plate is

  • Correct answer
    A
    2 λ
  • B
    2 λ 3
  • C
    λ 3
  • D
    λ

Solution

For no change of Intensity at central maxima there should again be maxima.

∴ Path difference due to slab should be integral multiple of λ 

or     Δx=nλ

or      μ - 1 t =  λ n = 1  ,  2  ,  3  ,........ 

or t = n λ μ - 1

For minimum value of t ,  n  = 1

t = λ μ - 1 = λ 1 · 5 - 1 = 2 λ

Hence, the correct answer is option: 'A'.

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