In a double-slit experiment, the separation between the slits is $d=0.25\text{cm}$ and the distance of the screen $D=100\text{cm}$ from the slits. If the wavelength of light used is $\lambda =6000 \stackrel{\circ }{\mathrm{A}}$  and $I_0$ is the intensity of the central bright fringe, the intensity at a distance $x=4\times {10}^{-5}\text{m}$ from central maximum is

• A

  $I_0$
• B

  $\frac{I_0}{2}$
• Correct answer
  C

  $\frac{\text{3}{\mathit{\text{I}}}_0}{4}$
• D

  $\frac{I_0}{3}$

Hence, the correct answer is option: 'C'.