Q159 / 170 · Manipal (MET) 2018 · Physics

In a step-up transformer the voltage in the primary is 220 V and the current is 5 A . The secondary voltage is found to be 22000 V . The current in the secondary (neglect losses) is

A
5 A
B
50 A
C
500 A
Correct answer
D
0.05 A

Solution

$\frac{V_s}{V_p}=\frac{I_s}{I_p}$ $\Rightarrow \quad I_s=I_p \times \frac{V_s}{V_p}=5 \times \frac{220}{22000}=0.05 \mathrm{~A}$

Hence, the correct answer is option: 'D'.

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