Q124 / 170 · Manipal (MET) 2018 · Physics

A transformer of $100 \%$ efficiency has 200 turns in the primary and 40000 turns in secondary. It is connected to a 220 V main supply and secondary feeds to a $100 \mathrm{k} \Omega$ resistance. The potential difference per turn is

  • Correct answer
    A
    1.1 V
  • B
    25 V
  • C
    18 V
  • D
    11 V

Solution

From transformer ratio $\begin{aligned} \frac{V_s}{V_p} & =\frac{N_s}{N_p} \\ \Rightarrow \quad V_s & =\frac{V_p \times N_s}{N_p} \\ & =\frac{220 \times 40000}{200} \\ & =44000 \mathrm{~V} \end{aligned}$
Potential difference per turn is $\frac{V_s}{N_s}=\frac{44000}{40000}=1.1 \mathrm{~V}$

Hence, the correct answer is option: 'A'.

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