Q73 / 90 · JEE Main 2024 (30 Jan Shift 1) · Physics

In a closed organ pipe, the frequency of fundamental note is 30 Hz. A certain amount of water is now poured in the organ pipe so that the fundamental frequency is increased to 110 Hz. If the organ pipe has a cross-sectional area of 2 cm2, the amount of water poured in the organ tube is ________g. (Take speed of sound in air is 330 m s-1 )

Correct answer: 400

Solution

Fundamental frequency for closed organ pipe in the first part:

V4l1=30⇒l1=114 m

Similarly, for second part:

V4l2=110⇒l2=34 m

Therefore, change in length Δl=2 m

Change in volume =AΔl=400 cm3

M=400 g;∵ρ=1 g cm-3

Hence, the correct answer is 400.

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