Q62 / 75 · JEE Main 2026 (24 January Shift 2) · Physics
The fifth harmonic of a closed organ pipe is found to be in unison with the first harmonic of an open pipe. The ratio of lengths of closed pipe to that of the open pipe is $5 / x$. The value of $x$ is $\_\_\_\_$.
- A3
- B4
- C1
- Correct answerD2
Solution
Fifth harmonic of closed organ pipe equals first harmonic of open pipe:
$f_{5\text{ closed}} = f_{1\text{ open}}$
$\frac{5v}{4L_{\text{closed}}} = \frac{v}{2L_{\text{open}}}$
$\frac{L_{\text{closed}}}{L_{\text{open}}} = \frac{5}{2}$
Since the ratio is $\frac{5}{x}$, we get $x = 2$.
$f_{5\text{ closed}} = f_{1\text{ open}}$
$\frac{5v}{4L_{\text{closed}}} = \frac{v}{2L_{\text{open}}}$
$\frac{L_{\text{closed}}}{L_{\text{open}}} = \frac{5}{2}$
Since the ratio is $\frac{5}{x}$, we get $x = 2$.
Hence, the correct answer is option: 'D'.