Q42 / 87 · NTA Abhyas (JEE Main) 2020 · Mathematics · Functions

If fx=x2-x2x2-x2-2 (where, ⋅ represents the greatest integer part of x), then the range of fx is

  • A
    0,1
  • B
    -1,1
  • C
    0,∞
  • Correct answer
    D
    0,13

Solution

We know that, x2-x2=x2
∴fx=x22+x2=2+x2-22+x2=1-22+x2
∴0≤x2<1⇒2≤x2+2<3
23<2x2+2≤1⇒-23>-22+x2≥-1
⇒13>1+-22+x2≥0

Hence, the range of fx is 0,13

Hence, the correct answer is option: 'D'.

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