Identify the correct statement for ${\mathrm{B}}_2{\mathrm{H}}_6$ from those given below.

(A) In ${\mathrm{B}}_2{\mathrm{H}}_6$, all $\mathrm{B}-\mathrm{H}$ bonds are equivalent.

(B) In ${\mathrm{B}}_2{\mathrm{H}}_6$, there are four $3$-centre- $2$-electron bonds.

(C) ${\mathrm{B}}_2{\mathrm{H}}_6$ is a Lewis acid.

(D) ${\mathrm{B}}_2{\mathrm{H}}_6$ can be synthesized from both ${\mathrm{BF}}_3$ and ${\mathrm{NaBH}}_4$.

(E) ${\mathrm{B}}_2{\mathrm{H}}_6$ is a planar molecule.

Choose the most appropriate answer from the options given below :

• A

  $\left(\mathrm{A}\right)$ and $\left(\mathrm{E}\right)$ only
• B

  $\left(\mathrm{B}\right),\left(\mathrm{C}\right)$ and $\left(\mathrm{E}\right)$ only
• Correct answer
  C

  $\left(\mathrm{C}\right)$ and $\left(\mathrm{D}\right)$ only
• D

  $\left(\mathrm{C}\right)$ and $\left(\mathrm{E}\right)$ only

Hence, the correct answer is option: 'C'.