Q16 / 90 · JEE Main 2022 (24 Jun Shift 2) · Chemistry
Hex--ene--ol on treatment with gives ''. '' on reaction with sodium hypoiodite gives '', which on further heating with soda lime gives ''. The compound '' is
- A-pentene
- Bproponaldehyde
- Correct answerC-butene
- D-methylpent--ene
Solution

Hex--ene--ol on reaction with PCC forms Hex--ene--one.
Hex--ene--one on iodoform reaction gives pent- enoic acid and iodoform.
Pent- enoic acid on decarboxylation with soda lime forms but--ene.
Hence, the correct answer is option: 'C'.