Q8 / 90 · JEE Main 2021 (27 Jul Shift 2) · Chemistry

Given below are two statements :
Statement I: Mn(CN)63-,  Fe(CN)63- and CoC2O433- are d2sp3 hybridised.
Statement II : MnCl63- and FeF63- are paramagnetic and have 4 and 5 unpaired electrons, respectively. 

In the light of the above statements, choose the correct answer from the options given below:

  • A
    Statement I is correct but statement II is false
  • B
    Both statement I and statement II are false
  • C
    Statement I is incorrect but statement II is true
  • Correct answer
    D
    Both statement I and statement II are are true

Solution

Figure

CN- is strong field ligand. C2O42- is chelating ligand. Mn3+ has d4 configuration. Fe3+ has d5 configuration. Co3+ has d6 configuration.

⇒ All will have larger splitting values hence, they undergo d2sp3 hybridisation.

MnCl63-                              FeF63-

d4 configuration, Cl-             d5 configuration, F-

Figure

Hence, the correct answer is option: 'D'.

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