Q12 / 75 · JEE Main 2026 (02 April Shift 1) · Chemistry

Match List - I with List - II.
List - I
Chromium (III) Complexes
(en = ethylene diamine)
List - II
$\Delta_0$ (cm$^{-1}$)
A. $[Cr(CN)_6]^{3-}$I. $15,060$
B. $[CrF_6]^{3-}$II. $17,400$
C. $[Cr(H_2O)_6]^{3+}$III. $22,300$
D. $[Cr(en)_3]^{3+}$IV. $26,600$

Choose the correct answer from the options given below :

  • A
    A-I, B-II, C-III, D-IV
  • B
    A-II, B-III, C-IV, D-I
  • C
    A-III, B-IV, C-I, D-II
  • Correct answer
    D
    A-IV, B-I, C-II, D-III

Solution

The crystal field splitting energy $\Delta_0$ depends on the strength of the ligand.

According to the spectrochemical series, the order of ligand strength is $F^- < H_2O < en < CN^-$.

Thus, the order of $\Delta_0$ for the given complexes is $[CrF_6]^{3-} < [Cr(H_2O)_6]^{3+} < [Cr(en)_3]^{3+} < [Cr(CN)_6]^{3-}$.

Matching with the given values:
$[CrF_6]^{3-}$ has the minimum $\Delta_0 = 15,060$ cm$^{-1}$ (B $\rightarrow$ I).
$[Cr(H_2O)_6]^{3+}$ has $\Delta_0 = 17,400$ cm$^{-1}$ (C $\rightarrow$ II).
$[Cr(en)_3]^{3+}$ has $\Delta_0 = 22,300$ cm$^{-1}$ (D $\rightarrow$ III).
$[Cr(CN)_6]^{3-}$ has the maximum $\Delta_0 = 26,600$ cm$^{-1}$ (A $\rightarrow$ IV).

This corresponds to A-IV, B-I, C-II, D-III.

Answer: A-IV, B-I, C-II, D-III

Hence, the correct answer is option: 'D'.

Relevant Questions