Four projectiles are fired with the same velocities at angles $25°,40°,55°$ and $70°$ with the horizontal. The range of projectile will be largest for the one projected at angle _____.

Range of projectile is given by $R=\frac{u^2\sin \left(2\theta \right)}{g}$

Range for projection angle $25°$ is $R_1=\frac{u^2\sin \left(2\times 25\right)}{g}$

Range for projection angle $40°$ is $R_2=\frac{u^2\sin \left(2\times 40\right)}{g}$

Range for projection angle $55°$ is $R_3=\frac{u^2\sin \left(2\times 55\right)}{g}$

Range for projection angle$70°$ is $R_4=\frac{u^2\sin \left(2\times 70\right)}{g}$

So range will be maximum for $40°$