Q124 / 160 · AP EAMCET 2025 (26 MAY SHIFT 2) · Physics
If the velocity at the maximum height of a projectile projected at an angle of $45^{\circ}$ is $20 \mathrm{~m} \mathrm{~s}^{-1}$, then the maximum height reached by the projectile is (Acceleration due to gravity $=10 \mathrm{~m} \mathrm{~s}^{-2}$ )
- A10 m
- Correct answerB20 m
- C30 m
- D40 m
Hence, the correct answer is option: 'B'.