If the horizontal range of a body projected with a velocity ' $u$ ' is 3 times the maximum height reached by it, then the range of the body is (g - acceleration due to gravity)

• A

  $\frac{2 \mathrm{u}^2}{3 \mathrm{~g}}$
• B

  $\frac{4 \mathrm{u}^2}{5 \mathrm{~g}}$
• C

  $\frac{12 \mathrm{u}^2}{13 \mathrm{~g}}$
• Correct answer
  D

  $\frac{24 \mathrm{u}^2}{25 \mathrm{~g}}$

Hence, the correct answer is option: 'D'.