Q29 / 222 · NTA Abhyas (NEET) 2020 · Physics · Wave Optics

For an interference pattern, the maximum and minimum intensity ratio is 64:1, then what will be the ratio of amplitudes?

  • A
    8:1
  • Correct answer
    B
    9:7
  • C
    1:8
  • D
    7:9

Solution

Since, we know,

ImaxImax=a1a2+1a1a2-12

Given, ImaxImin=641

⇒641=a1+a2a1-a22

⇒a1+a2a1-a2=8

⇒a1a2=8+18-1=97

∴ a1a2=97

Hence, the correct answer is option: 'B'.

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