Q72 / 170 · Manipal (MET) 2016 · Mathematics
$\int \frac{\left(2 x^{12}+5 x^9\right)}{\left(1+x^3+x^5\right)^3} d x$ equals
- Correct answerA$\frac{x^{10}}{2\left(x^5+x^3+1\right)^2}+C$
- B$\frac{x^2+2 x}{\left(x^5+x^3+1\right)}+C$
- C$\left.\log \left(x^5+x^3+1+\sqrt{\left(2 x^{12}+5 x^9\right)}+C\right)\right]$
- DNone of the above
Solution
Let
$I=\int \frac{2 x^{12}+5 x^9}{\left(1+x^3+x^5\right)^3} d x=\int \frac{5 x^{-6}+2 x^{-3}}{\left(1+x^{-2}+x^{-5}\right)^3} d x$
Put $1+x^{-2}+x^{-5}=t,\left(-2 x^{-3}-5 x^{-6}\right) d x=d t$
$\therefore \quad I=-\int \frac{d t}{t^3}=\frac{1}{2 t^2}=\frac{1}{2\left(1+x^{-2}+x^{-5}\right)^2}$
$=\frac{x^{10}}{2\left(x^5+x^3+1\right)^2}+C$
Hence, the correct answer is option: 'A'.