Q73 / 170 · Manipal (MET) 2016 · Mathematics
$\left|\begin{array}{ccc}\sin \theta & \cos \theta & \sin 2 \theta \\ \sin \left(\theta+\frac{2 \pi}{3}\right) & \cos \left(\theta+\frac{2 \pi}{3}\right) & \sin \left(2 \theta+\frac{4 \pi}{3}\right) \\ \sin \left(\theta-\frac{2 \pi}{3}\right) & \cos \left(\theta-\frac{2 \pi}{3}\right) & \sin \left(2 \theta-\frac{4 \pi}{3}\right)\end{array}\right|$
equals
- A$3 \sin \theta$
- B$\sin ^3 \theta$
- Correct answerC$0$
- DNone of these
Solution
$\Delta=\left|\begin{array}{ccc}\sin \theta & \cos \theta & \sin 2 \theta \\ \sin \left(\theta+\frac{2 \pi}{3}\right) & \cos \left(\theta+\frac{2 \pi}{3}\right) & \sin \left(2 \theta+\frac{4 \pi}{3}\right) \\ \sin \left(\theta-\frac{2 \pi}{3}\right) & \cos \left(\theta-\frac{2 \pi}{3}\right) & \sin \left(2 \theta-\frac{4 \pi}{3}\right)\end{array}\right|$
$=\left|\begin{array}{ccc}\sin \theta & \cos \theta & \sin 2 \theta \\ 2 \sin \theta \cos \frac{2 \pi}{3} & 2 \cos \theta \cos \frac{2 \pi}{3} & 2 \sin 2 \theta \cos \frac{4 \pi}{3} \\ \sin \left(\theta-\frac{2 \pi}{3}\right) & \cos \left(\theta-\frac{2 \pi}{3}\right) & \sin \left(2 \theta-\frac{4 \pi}{3}\right)\end{array}\right|$
Applying $R_2 \rightarrow R_2+R_3$,
$=-\left|\begin{array}{ccc}\sin \theta & \cos \theta & \sin 2 \theta \\ \sin \theta & \cos \theta & \sin 2 \theta \\ \sin \left(\theta-\frac{2 \pi}{3}\right) & \cos \left(\theta-\frac{2 \pi}{3}\right) & \sin \left(2 \theta-\frac{4 \pi}{3}\right)\end{array}\right|=0$
as $R_1=R_2$
Hence, the correct answer is option: 'C'.