Q94 / 170 · Manipal (MET) 2021 · Mathematics
$\cdot \int_{-\frac{\pi}{2}}^{\frac{\pi}{2}}|\sin x| d x$ is
- Correct answerA2
- B0
- C$\frac{\pi}{2}$
- D1
Solution
$\begin{aligned} \int_{-\pi / 2}^{\pi / 2}|\sin x| d x & =2 \int_0^{\pi / 2} \sin x d x \\ & =2[-\cos x]_0^{\pi / 2}=2\end{aligned}$
Hence, the correct answer is option: 'A'.