Q94 / 170 · Manipal (MET) 2015 · Mathematics
$\int_1^4 \log _e[x] d x$ equals
- A$\log _8 2$
- B$\log _\theta 3$
- Correct answerC$\log _e 6$
- DNone of the above
Solution
Let $I=\int_1^4 \log _\theta[x] d x$
$\begin{aligned} & =\int_1^2 \log _\theta 1 d x+\int_2^3 \log _\theta 2 d x+\int_3^4 \log _\theta 3 d x \\ & =\log _e 2+\log _e 3=\log _e 6\end{aligned}$
Hence, the correct answer is option: 'C'.