Choose the correct sequence of reagents in the conversion of 4-nitrotoluene to 2 -bromotoluene.

• Correct answer
  A

  $\mathrm{Br}_2 ; \mathrm{Sn} / \mathrm{HCl} ; \mathrm{NaNO}_2 / \mathrm{HCl} ; \mathrm{H}_2 \mathrm{O} / \mathrm{H}_3 \mathrm{PO}_2$
• B

  $\mathrm{Sn} / \mathrm{HCl} ; \mathrm{Br}_2 ; \mathrm{NaNO}_2 / \mathrm{HCl} ; \mathrm{H}_2 \mathrm{O} / \mathrm{H}_3 \mathrm{PO}_2$
• C

  $\mathrm{NaNO}_2 / \mathrm{HCl} ; \mathrm{Sn} / \mathrm{HCl} ; \mathrm{Br}_2 ; \mathrm{H}_2 \mathrm{O} / \mathrm{H}_3 \mathrm{PO}_2$
• D

  $\mathrm{Sn} / \mathrm{HCl} ; \mathrm{NaNO}_2 / \mathrm{HCl} ; \mathrm{Br}_2 ; \mathrm{H}_2 \mathrm{O} / \mathrm{H}_3 \mathrm{PO}_2$

Hence, the correct answer is option: 'A'.