Q88 / 200 · NEET 2021 · Chemistry
Match List - I with List - II.
List-I List-II (a) 
(i) Hell-Volhard-Zelinsky reaction (b) 
(ii) Gattermann-Koch reaction (c) 
(iii) Haloform reaction (d) 
(iv) Esterification
Choose the correct answer from the options given below.
Match List - I with List - II.
| List-I | List-II | ||
| (a) | ![]() | (i) | Hell-Volhard-Zelinsky reaction |
| (b) | ![]() | (ii) | Gattermann-Koch reaction |
| (c) | ![]() | (iii) | Haloform reaction |
| (d) | ![]() | (iv) | Esterification |
Choose the correct answer from the options given below.
- A(a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)
- B(a)-(iii), (b)-(ii), (c)-(i), (d)-(iv)
- C(a)-(i), (b)-(iv), (c)-(iii), (d)-(ii)
- Correct answerD(a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)
Solution
This reaction is Gattermann- Koch reaction (ii) in which benzaldehye is formed.
This reaction is haloform reaction (iii) which is given by methyl ketones and produce haloform as one of the product.
This reaction is esterification (iv) reaction which involves the formation of ester by reaction of aldehyde and ketone.
This reaction is HVZ reaction (i), which involves alpha halogenation of carboxylic acid.Hence, the correct answer is option: 'D'.