Q92 / 200 · NEET 2023 (Manipur) · Chemistry
Reagents which can be used to convert alcohols to carboxylic acids, are
(A) $\mathrm{CrO}_3-\mathrm{H}_2 \mathrm{SO}_4$
(B) $\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7+\mathrm{H}_2 \mathrm{SO}_4$
(C) $\mathrm{KMnO}_4+\mathrm{KOH} / \mathrm{H}_3 \mathrm{O}^{+}$
(D) $\mathrm{Cu}, 573 \mathrm{~K}$
(E) $\mathrm{CrO}_3,\left(\mathrm{CH}_3 \mathrm{CO}\right)_2 \mathrm{O}$
Choose the most appropriate answer from the options given below.
- Correct answerA$(A),(B)$ and $(C)$ only
- B$(A),(B)$ and $(E)$ only
- C$(B),(C)$ and $(D)$ only
- D$(B),(D)$ and $(E)$ only
Solution
- $\mathrm{R}-\mathrm{CH}_2 \mathrm{OH} \frac{\text { 1. alkaline } \mathrm{KMnO}_4}{2 \cdot \mathrm{H}_3 \mathrm{O}^{+}} \longrightarrow \mathrm{R}-\mathrm{COOH}$
- $\mathrm{CH}_3\left(\mathrm{CH}_2\right)_8 \mathrm{CH}_2 \mathrm{OH} \frac{\mathrm{CrO}_3 \cdot \mathrm{H}_2 \mathrm{SO}_4}{\text { Jones reagent }} \rightarrow \mathrm{CH}_3\left(\mathrm{CH}_2\right)_8 \mathrm{COOH}$
- Alcohols can be easily oxidised by $\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7$ and $\mathrm{CrO}_3$ in acidic medium.
Hence, the correct answer is option: 'A'.