As a result of change in the magnetic flux linked to the closed loop as shown in the figure, an e.m.f. $V$ volt is induced in the loop. The work done (joules) in taking a charge $Q$ coulomb once along the loop is:

• Correct answer
  A

  $Q V$
• B

  $2 Q V$
• C

  $\frac{Q V}{2}$
• D

  zero

Hence, the correct answer is option: 'A'.