Q101 / 160 · WBJEE 2011 · Mathematics

\(\left|\begin{array}{lll}a-b & b-c & c-a \\ b-c & c-a & a-b \\ c-a & a-b & b-c\end{array}\right|=\)

  • Correct answer
    A
    0
  • B
    -1
  • C
    1
  • D
    2

Solution

Hints : \(\mathrm{c}_1 \rightarrow \mathrm{c}_1+\mathrm{c}_2+\mathrm{c}_3\)

Hence, the correct answer is option: 'A'.

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