Q6 / 225 · JEE Main 2005 · Chemistry

An ionic compound has a unit cell consisting of A ions at the corners of a cube and B ions on the centres of the faces of the cube. The empirical formula for this compound would be

  • A
    $\mathrm{A}\mathrm{~B}$
  • B
    $\mathrm{A}_2 \mathrm{~B}$
  • Correct answer
    C
    $\mathrm{A}\mathrm{~B}_3$
  • D
    $\mathrm{A}_3 \mathrm{~B}$

Solution

$$ A=\frac{1}{8} \times 8=1 $$ (Corner) $\mathrm{B}=\frac{1}{2} \times 6=3$ (Face centre) $\therefore \mathrm{AB}_3$

Hence, the correct answer is option: 'C'.

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