Q130 / 180 · NEET 2019 (All India) · Physics

An electron is accelerated through a potential difference of $10,000 V .$ Its de Broglie wavelength is (nearly): $(m_{e} = 9 \times 1 0^{- 31} k g)$

A
$12.2 \times 10^{- 13} m$
Correct answer
B
$12.2 \times 10^{- 12} m$
C
$12.2 \times 10^{- 14} m$
D
$12.2 n m$

Solution

The energy of electron

K

= 10^{4} e V

λ = \frac{h}{m v} = \frac{h}{\sqrt{2 m K}} = \frac{6.63 \times 10^{- 34}}{\sqrt{2 \times 9.1 \times 10^{- 31} \times 10^{4} \times 1.6 \times 10^{- 19}}} ≅ 12.2 \times 10^{- 12} m

Hence, the correct answer is option: 'B'.

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