An electromagnetic wave, travelling in vacuum, is represented by $\vec{E}=E_0 \cos (k z-v t) \hat{y}$ where $E_0$ is the amplitude of the electric field. A square loop of side a $(a \ll 2 \pi / k)$ is placed in its path. Then, the correct option(s) is (are)

• Correct answer
  A

  $\vec{B}=B_0 \cos (k z-w t) \hat{x}$ where $B_0=-E_0 / c$
• B

  The wave is travelling in the $y$-direction.
• Correct answer
  C

  The induced emf is zero if the loop lies in the $x z$ plane.
• Correct answer
  D

  The induced emf is finite if the loop lies in the $y z$ plane.

Hence, the correct answer is options: 'A', 'C', 'D'.