Q3 / 103 · NTA Abhyas (NEET) 2020 · Physics · Motion In One Dimension

Acceleration velocity graph of a particle moving in a straight line is as shown in figure. The slope of velocity-displacement graph

Figure

  • A
    increases linearly
  • B
    decreases linearly
  • Correct answer
    C
    is constant
  • D
    increases parabolically

Solution

From the acceleration-velocity graph, we have a=k v where k is a constant which represents the slope of the given line.

As, a=vdvds, so vdvds=kv

or dvds=k=a constant

Thus, the slope of the velocity-displacement graph is the same as that of acceleration-velocity. Which is constant.

Hence, the correct answer is option: 'C'.

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