Q8 / 103 · NTA Abhyas (NEET) 2020 · Physics · Motion In One Dimension

A and B participate in a race with acceleration a1 and a2, respectively. A reaches t times earlier than B at finish line and their velocities at finish line are v1 and v2, respectively. If difference between their velocities is v, then find the value of v

  • A
    a1+a22t
  • Correct answer
    B
    a1a2t
  • C
    a1a2a1+a2t
  • D
    2a1a2a1+a2t

Solution

12a1t02=12a2t0+t2

v1=a1t0v2=a2t0+t

v=v1-v2=a1-a2t0-a2t

a1a2  t0=t0+t

t0=ta1a2-1

v=a1-a2ta1a2-1-a2t

=ta1a2a1-a2-a2a2a1-a2-a2

=ta1a2-a2a1a1-a2

=ta1 a2

Hence, the correct answer is option: 'B'.

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