Q94 / 180 · NEET 2020 (Phase 1) · Physics

A wire of length L, area of cross section A is hanging from a fixed support. The length of the wire changes to L1 when mass M is suspended from its free end. The expression for Young's modulus is:

  • A
    MgL1−LAL
  • B
    MgLAL1
  • Correct answer
    C
    MgLAL1−L
  • D
    MgL1AL

Solution

We know that, 

Young's modulus, Y=FLAΔL

Given,

F=Weight of suspended body=Mg and ∆L=L1-L.

So, we can write

Y=MgLAL1-L

Hence, the correct answer is option: 'C'.

Relevant Questions