Q93 / 180 · NEET 2020 (Phase 1) · Physics

A body weighs $72 N$ on the surface of the earth. What is the gravitational force on it, at a height equal to half the radius of the earth?

Correct answer
A
$32 N$
B
$30 N$
C
$24 N$
D
$48 N$

Solution

$W_{s} = m g_{s} = 72 N$

$W_{h} = m g_{h} = \frac{m g_{s}}{{(1 + \frac{h}{R})}^{2}} = \frac{72 N}{{(1 + \frac{R / 2}{R})}^{2}} = \frac{72}{9 / 4}$

$W_{h} = 32 N$

Hence, the correct answer is option: 'A'.

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