Q95 / 180 · NEET 2020 (Phase 1) · Physics

A capillary tube of radius $r$ is immersed in water and water rises in it to a height $h$ . The mass of the water in the capillary is $5 g$ . Another capillary tube of radius $2 r$ is immersed in water. The mass of water that will rise in this tube is:

Solution

The relation between mass and radius of the capillary tube is given by, $\begin{array}{l} m \propto r \end{array}$

$\begin{array}{l} \Rightarrow \frac{m_{2}}{m_{1}} = \frac{r_{2}}{r_{1}} \end{array}$

$\Rightarrow \frac{m_{2}}{5} = \frac{2 r}{r}$

$\Rightarrow m_{2} = 10 g$

Hence, the correct answer is option: 'B'.