Q21 / 90 · JEE Main 2012 (07 May Online) · Chemistry

A solid has a ' $b c c$ ' structure. If the distance of nearest approach between two atoms is $1.73 Å$, the edge length of the cell is

  • A
    $314.20 \mathrm{pm}$
  • B
    $1.41 \mathrm{pm}$
  • Correct answer
    C
    $200 \mathrm{pm}$
  • D
    $216 \mathrm{pm}$

Solution

For bcc structure $$ d=\frac{\sqrt{3} a}{2} $$ where $d=$ distance between two atoms $a=$ edge length $$ \begin{aligned} & 1.73=\frac{\sqrt{3}}{2} a \\ & a=\frac{2 \times 1.73}{\sqrt{3}}=2 Å=200 \mathrm{pm} \end{aligned} $$

Hence, the correct answer is option: 'C'.

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