Q104 / 200 · NEET 2004 · Physics
A particle of mass $m_1$ is moving with a velocity $v_1$ and another particle of mass $m_2$ is moving with a velocity $v_2$. Both of them have the same momentum but their different kinetic energies are $E_1$ and $E_2$ respectively. If $m_1>m_2$ then:
- Correct answerA$E_1 < E_2$
- B$\frac{E_1}{E_2}=\frac{m_1}{m_1}$
- C$E_1>E_2$
- D$E_1=E_2$
Solution
We know that K.E. $=\frac{P^2}{2 m}$
$$
\begin{array}{ll}
\therefore & \frac{E_1}{E_2}=\frac{P_1^2 / 2 m_1}{P_2^2 / 2 m_2} \\
\Rightarrow \quad \frac{E_1}{E_2}=\frac{m_2}{m_1}
\end{array}
$$
Here $\quad m_1=m_2$
$$
\therefore \quad E_1 < E_2
$$
Hence, the correct answer is option: 'A'.