Q94 / 180 · NEET 2016 (Phase 2) · Physics

A bullet of mass 10 g moving horizontally with a velocity of 400 m s-1 strikes a wooden block of mass 2 kg which is suspended by a light inextensible string of length 5 m. As a result, the centre of gravity of the block is found to rise a vertical distance of 10 cm. The speed of the bullet after it emerges out horizontally from the block will be

  • A
    100 m s-1
  • B
    80 m s-1
  • Correct answer
    C
    120 m s-1
  • D
    160 m s-1

Solution

CM rises through height h, so its velocity after collision =2gh

Apply conservation of linear momentum.

0.01×400=2×2gh+0.01×v

⇒v=120 m/s

Hence, the correct answer is option: 'C'.

Relevant Questions