A mixture of hydrogen and oxygen has volume 2000 cm^3, temperature 300 K, pressure 100kPa and mass 0.76 g. The ratio of number of moles of hydrogen to…

Question

A mixture of hydrogen and oxygen has volume $2000 {cm}^{3}$ , temperature $300 K$ , pressure $100 kPa$ and mass $0.76 g$ . The ratio of number of moles of hydrogen to number of moles of oxygen in the mixture will be

[Take gas constant $R = 8.3 J K^{- 1} {mol}^{- 1}$ ]

MARKS Content Team · Accepted Answer

Correct answer: (B) 3/1. From the ideal gas equation, total number of moles in the mixture are, n=PV/RT=(2×10^(-3)×100×10^3×3)/(25×300)⇒n=2/25=0.08 If number of moles of oxygen are n_1 and of hydrogen are n_2 n_1+n_2=n=0.08…1 And total mass of the mixture n_132+n_22=0.76…2 Solving the above equations, n_1=0.02 and n_2=0.06 n_2n_1=3

A mixture of hydrogen and oxygen has volume $2000 {cm}^{3}$ , temperature $300 K$ , pressure $100 kPa$ and mass $0.76 g$ . The ratio of number of moles of hydrogen to number of moles of oxygen in the mixture will be
[Take gas constant $R = 8.3 J K^{- 1} {mol}^{- 1}$ ]

Solution

Relevant Questions

A mixture of hydrogen and oxygen has volume 2000 cm3, temperature 300 K, pressure 100kPa and mass 0.76 g. The ratio of number of moles of hydrogen to number of moles of oxygen in the mixture will be[Take gas constant R=8.3 J K-1 mol-1]

Solution

Relevant Questions

A mixture of hydrogen and oxygen has volume $2000 {cm}^{3}$ , temperature $300 K$ , pressure $100 kPa$ and mass $0.76 g$ . The ratio of number of moles of hydrogen to number of moles of oxygen in the mixture will be
[Take gas constant $R = 8.3 J K^{- 1} {mol}^{- 1}$ ]