Q81 / 90 · JEE Main 2022 (27 Jun Shift 1) · Physics

In a carnot engine, the temperature of reservoir is $527 ° C$ and that of sink is $200 K$ . If the workdone by the engine when it transfers heat from reservoir to sink is $12000 kJ$ , the quantity of heat absorbed by the engine from reservoir is _____ $\times 10^{6} J$ .

Correct answer: 16

Solution

Efficiency of Carnot engine is $η = 1 - \frac{T_{L}}{T_{H}} = \frac{W}{Q}$ , where, $Q$ is heat absorbed.

Here, $T_{H} = 527 + 273 = 800 K$

Now, $η = 1 - \frac{200}{800} = \frac{12}{Q}$

$∴ \frac{3}{4} = \frac{12000}{Q}$

$∴ Q = 16 \times 10^{6} J$

Hence, the correct answer is 16.