Q151 / 160 · AP EAMCET 2022 (04 Jul Shift 2) · Physics

A magnetic needle free to rotate in a vertical plane parallel to the magnetic meridian has its north tip pointing down at $30 °$ with the horizontal. The horizontal component of the earth's magnetic field at the place is $0.3 G$ . Then the magnitude of the earth's magnetic field at the location is

Correct answer
A
$\frac{\sqrt{3}}{5} G$
B
$\sqrt{3} G$
C
$\frac{20}{\sqrt{3}} G$
D
$\frac{2}{\sqrt{3}} G$

Solution

Horizontal component magnetic field at a point where dip angle is $δ$ is given by,
$B_{H} = B \cos δ \Rightarrow B = \frac{B_{H}}{\cos δ} = \frac{0.3 \times 2}{\sqrt{3}} = \frac{\sqrt{3}}{5} G$

Hence, the correct answer is option: 'A'.

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A magnetic needle free to rotate in a vertical plane parallel to the magnetic meridian has its north tip pointing down at 30° with the horizontal. The horizontal component of the earth's magnetic field at the place is 0.3G. Then the magnitude of the earth's magnetic field at the location is

Solution

Relevant Questions

A magnetic needle free to rotate in a vertical plane parallel to the magnetic meridian has its north tip pointing down at $30 °$ with the horizontal. The horizontal component of the earth's magnetic field at the place is $0.3 G$ . Then the magnitude of the earth's magnetic field at the location is