Q147 / 160 · AP EAMCET 2022 (08 Jul Shift 1) · Physics

Two identical thin bar magnets each of length $l$ and pole strength $m$ are placed at right angles to each other with north-pole of one touching south-pole of the other, then the magnetic moment of the system is

  • A
    $\mathrm{ml}$
  • B
    $2 \mathrm{ml}$
  • Correct answer
    C
    $\sqrt{2} \mathrm{ml}$
  • D
    $\mathrm{ml} / 2$

Solution

Here, distance between two poles $=\sqrt{2} 1$ Hence, $\mathrm{M}=\mathrm{m} \times \sqrt{2} \mathrm{l}=\sqrt{2} \mathrm{ml}$

Hence, the correct answer is option: 'C'.

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