A certain buffer solution contains equal concentration of X^(-) and HX. The K_b for X^(-) is 10^(-10). The pH of the buffer is

Question

MARKS Content Team · Accepted Answer

Correct answer: (A) 4. X^(−) + H_2 O ⇌ OH^(−) + HX K_b=([OH^(-)][HX])/([X^(-)]) HX ⇌ H^(+) + X^(−) K_a=([H^(+)][X^(-)])/([HX]) ∴K_a×K_b=[H^(+)][OH^(-)]=K_w=10^(-14) Hence K_a=10^(-4) Now as [X^(-)]=[HX],pH=pK_a=4 .

A certain buffer solution contains equal concentration of $X^{-}$ and $H X .$ The $K_{b}$ for $X^{-}$ is $1 0^{- 10} .$ The $p H$ of the buffer is

Solution

More Ionic Equilibrium Questions

A certain buffer solution contains equal concentration of X- and HX. The Kb for X- is 10-10. The pH of the buffer is

Solution

More Ionic Equilibrium Questions

A certain buffer solution contains equal concentration of $X^{-}$ and $H X .$ The $K_{b}$ for $X^{-}$ is $1 0^{- 10} .$ The $p H$ of the buffer is