Q123 / 160 · AP EAMCET 2017 (25 Apr Shift 2) · Physics

A body is projected with a velocity $(\hat{\mathrm{i}}+2 \hat{\mathrm{j}}) \mathrm{ms}^{-1}$, where $\hat{\mathrm{i}}$ is along the horizontal and $\hat{\mathrm{j}}$ is vertically upward. Then the equation of its trajectory is $\left(\mathrm{g}=10 \mathrm{~ms}^{-2}\right)$

  • A
    $y=x-5 x^2$
  • Correct answer
    B
    $y=2 x-5 x^2$
  • C
    $y=2 x+5 x^2$
  • D
    $y=x+5 x^2$

Hence, the correct answer is option: 'B'.

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