Q123 / 160 · AP EAMCET 2017 (25 Apr Shift 2) · Physics
A body is projected with a velocity $(\hat{\mathrm{i}}+2 \hat{\mathrm{j}}) \mathrm{ms}^{-1}$, where $\hat{\mathrm{i}}$ is along the horizontal and $\hat{\mathrm{j}}$ is vertically upward. Then the equation of its trajectory is $\left(\mathrm{g}=10 \mathrm{~ms}^{-2}\right)$
- A$y=x-5 x^2$
- Correct answerB$y=2 x-5 x^2$
- C$y=2 x+5 x^2$
- D$y=x+5 x^2$
Hence, the correct answer is option: 'B'.