Q82 / 90 · JEE Main 2022 (26 Jun Shift 2) · Physics

A batsman hits back a ball of mass $0.4 kg$ straight in the direction of the bowler without changing its initial speed of $15 {m s}^{- 1}$ . The impulse imparted to the ball is _____ $N s$ .

Correct answer: 12

Solution

Impulse, $J = \int F d t =$ Change in momentum

Therefore,
Impulse, $Δ p = m v - (- m v) = 2 m v = 2 \times 0.4 \times 15 = 12 N s$

Hence, the correct answer is 12.

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