Q66 / 90 · JEE Main 2024 (30 Jan Shift 1) · Physics

A spherical body of mass 100 g is dropped from a height of 10 m from the ground. After hitting the ground, the body rebounds to a height of 5 m. The impulse of force imparted by the ground to the body is given by: (given g=9.8 m s-2)

  • A
    4.32 kg m s-1
  • B
    43.2 kg m s-1
  • C
    23.9 kg m s-1
  • Correct answer
    D
    2.39 kg m s-1

Solution

Using equation of motion with constant acceleration, we can write:

v1=2gh1 and v2=2gh2

Now, required impulse

I→=Δp→=p→f-p→i

Given, M=0.1 kg

Therefore,

I=Δp=0.1(2×9.8×5-(-2×9.8×10))

=0.1(72+14)≈2.39 kg m s-1

Hence, the correct answer is option: 'D'.

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